We suggest considering the following factors when selecting your race: Time Frame The faster train passes the slower train in 36 seconds.The first step in starting your marathon journey is choosing a marathon! There are hundreds of marathons held every year all over the world, from the “Big Five” (Berlin, Boston, Chicago, London and New York City) to smaller, local events held just about everywhere. Q 3: Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The time taken by the slower train to cross the faster train in seconds is: Their lengths are 1.10 km and 0.9 km respectively. Q 2: Two trains are moving in opposite directions at a speed of 60 km/hr and 90 km/hr respectively. In how much time will the train pass the jogger? Q 1: A jogger running at 9 km/h alongside a railway track in 240 meters ahead of the engine of a 120 meters long train running at 45 km/h in the same direction. Also, we know that the formula for finding Time = ( Distance/Speed ) Thus the total distance to be covered = (360 + 140) m = 500 m. In what time will it pass a bridge 140 m long?Īnswer: We have already seen the formula for converting from km/hr to m/s: x km/hr =m/s. Hence the correct option here is B) 3:2Įxample 4: A train 360 m long is running at a speed of 45 km/hr. Then, the length of the first train = 27x meters, and length of the second train = 17y meters. The ratio of their speeds is:Īnswer: Let the speeds of the two trains be = x m/s and y m/s respectively. Therefore, the correct option is C) 50 km/h.Įxample 3: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. Therefore, we must have, (x – 5) = 45 or x = 50 km/hr. Then, the relative speed of the train with respect to the man = (x – 5) km/hr. Now, let the speed of the train be = x km/hr. In other words we can write, this speed = ( (25/2) × (18/5) ) km/hr = 45 km/hr. Therefore, this speed of the train = ( 25/2 )m/sec. Hence if the man was at rest or we can with respect to the man = ( 125/10 )m/sec If the two objects are moving in the same direction, then their relative speed is equal to the difference between the two speeds.
![other words for running a train other words for running a train](http://giordanos.com/content/uploads/5-the-l.jpg)
The relative speed of two objects is the sum of their individual speeds if they are moving opposite to each other. Then the speed of the train is:Ī) 60 km/h B) 66 km/h C) 50 km/h D) 55 km/hĪnswer: Here we will have to use the concept of the relative speed. It takes the train 10 seconds to cross the man completely. It passes a man, running at 5 km/hr in the same direction in which the train is going. Browse more Topics under Time And SpeedĮxample 2: A certain train is 125 m long. Let us see some more examples that can be formulated on the basis of this concept. Therefore the correct option is D) 150 meters. In other words, we have the Distance = (50/3 m/s)×9 = 150 m. Therefore in 9 seconds, the train will cover a distance = speed×time We have the speed of the train = 60 km/hr or 60×(5/18) = 50/3 m/s. Therefore if the speed is ‘x’ km/hr then we can change it to m/s by multiplying x with 5/18.
![other words for running a train other words for running a train](https://runninforsweets.com/wp-content/uploads/2020/08/Running-Words-Pin-1-627x1024.png)
Let us see the trick to convert km/hr to m/s: We have the speed of the train = 60 km/hr. Thus we can get the length of the train by calculating the distance that the train travels in 9 seconds. This means that from the point when the engine or the front of the train crosses the pole to the point when the back of the train reaches the pole, we have 9 seconds. What is the length of the train?Ī) 200 meters B) 180 meters C) 376 meters D) 150 metersĪnswer: The train crosses the pole in 9 seconds. It crosses a certain pole that is in the way in 9 seconds. Here we shall see some examples of this concept and then learn some tricks from other examples.Įxample 1: A train running at the speed of 60 km/hr. The same formulae that we saw already are applicable here too. Since the size of the trains is comparable to the distances that they may travel, then we will have to take the size or the length of the trains into account too. Due to the small size of the cars and other objects, we take them as point objects.